¡@

Discovery Project

--- The Intersection of Three Cylinders

Download Maple Worksheet

¡@

1.

[Maple Plot]

The solid enclosed by the three cylinders x^2+y^2 = 1 , x^2+z^2 = 1 , and y^2+z^2 = 1  is shown above; where the green surface is the cylinder   x^2+z^2 = 1 , the blue surface is the cylinder   y^2+z^2 = 1 , and the yellow surface is the cylinder  x^2+y^2 = 1 .

¡@

¡@

2.

To find the volume, we can split the solid into sixteen congruent pieces, one of which lies in the part of the first octant with theta  in [0, Pi/4],as shown below.

[Maple Plot]

This piece is described by  

{  (r,theta,z)  |  0 <= rand r <= 1 0 <= theta and theta <= Pi/4, 0 <= zand z <= sqrt(1-(r*cos(theta))^2)}.

So the volume of the solid is

16*int(int(int(r,z = 0 .. sqrt(1-(r*cos(theta))^2)),r = 0 .. 1),theta = 0 .. Pi/4)

=16*int(int(r*sqrt(1-r^2*cos(theta)^2),r = 0 .. 1),theta = 0 .. Pi/4)

= 16-8*sqrt(2)                                   .

       

we can also split the solid into forty eight congruent pieces as follows :

[Maple Plot]

One of the piece which lies in the part of the first octant is shown below.

[Maple Plot]

This piece is described by  

{ (r,theta,z) | 0 <= rand r <= 1, 0 <= thetaand theta <= Pi/4,0 <= zand z <= r*sin(theta)}.

So the volume of the solid is

48*int(int(int(r,z = 0 .. r*sin(theta)),r = 0 .. 1),theta = 0 .. Pi/4)

 =    48*int(int(r^2*sin(theta),r = 0 .. 1),theta = 0 .. Pi/4)       

=   48*(2-sqrt(2))/6 = 16-8*sqrt(2) .

¡@

3.

One possible set of parametric equations ( with all sign choices allowed ) of the edges of the solid is

x = r,  y = ror y = -r z = sqrt(1-r^2) or z = -sqrt(1-r^2) for all r  in [-1/sqrt(2),1/sqrt(2)] .

x = sor x = -s, y = sqrt(1-s^2)or y = -sqrt(1-s^2), z = s for all s in [-1/sqrt(2),1/sqrt(2)] .

x = sqrt(1-t^2)or  x = -sqrt(1-t^2),  y = t,  z = t or  z = -t for all t in [-1/sqrt(2),1/sqrt(2)] .

[Maple Plot]

¡@

4. Let the three cylinder be x^2+y^2 = a,  x^2+z^2 = 1, and   y^2+z^2 = 1 .

(a) If a < 1 , the four faces in problem 1 collapse into a single face, as in the graph below.

a := .9

[Maple Plot]

(b) If 1<a<sqrt(2), then each pair of vertical opposite faces, defined by one of the other two cylinders, collapse into a single face. The graph of the case for a = 2/sqrt(3) is shown below.

[Maple Plot]

(c) If sqrt(2) <= a, then the solid of intersection coincides with the solid of intersection of the two cylinder x^2+z^2 = 1 , and   y^2+z^2 = 1, as in the graph below, where the blue surface is the cylinder x^2+z^2 = 1 , and the green surface is the cylinder y^2+z^2 = 1 .

[Maple Plot]

5.  

(a) If a < 1 , we split the solid into sixteen congruent pieces, one of which can be described as the solid above the polar region

{ (r,theta) | 0 <= r and r <= a, 0 <= theta and theta <= Pi/4 }

in the xy-plane and below the surface z = sqrt(1-r^2*cos(theta)^2), as shown below.

[Maple Plot]

Thus, the total volume is

     16*int(int(r*sqrt(1-r^2*cos(theta)^2),r = 0 .. a),theta = 0 .. Pi/4)  .

(b) If 1<a<sqrt(2), we split the solid into sixteen congruent pieces, one of which is the solid above the regions R[1], R[2]  and below the surface z = sqrt(1-x^2), where R[1] is the right triangular region

{ (x,y) | 0 <= x and x <= 1, 0 <= y and y <= sqrt(a^2-1)*x  } ,

and R[2]  is the circular polar region  

{ (r,theta) | 0 <= r and r <= a, arccos(1/a) <= theta  and theta <= Pi/4  } .

( as the figure below).

[Maple Plot] [Maple Plot]

Using rectangular coordinates for the region R[1] and polar coordinates for the region R[2]  , we find the total volume of the solid to be

16*int(int(sqrt(1-x^2),y = 0 .. sqrt(a^2-1)*x),x = 0 .. 1)+16*int(int(r*sqrt(1-r^2*cos(theta)^2),r = 0 .. a),theta = arcsos(1/a) .. Pi/4) .

¡@

(c) If sqrt(2) < a , we split the solid into sixteen congruent pieces, one of which can be described as the solid above the region { (x,y) | 0 <= xand x <= 1 , 0 <= y  and y <= x  } in the xy -plane and below the surface z = sqrt(1-x^2)  ,as shown below.

[Maple Plot]

Thus, the total volume is

16*int(int(sqrt(1-x^2),y = 0 .. x),x = 0 .. 1).


Download Maple Worksheet